Optimal. Leaf size=105 \[ \frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 x \left (a-b x^3\right )^2}{140 a^2 \left (a+b x^3\right )^{7/3}}+\frac{57 x \left (a-b x^3\right )}{280 a^2 \left (a+b x^3\right )^{4/3}}+\frac{171 x}{280 a^2 \sqrt [3]{a+b x^3}} \]
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Rubi [A] time = 0.0353146, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {382, 378, 191} \[ \frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 x \left (a-b x^3\right )^2}{140 a^2 \left (a+b x^3\right )^{7/3}}+\frac{57 x \left (a-b x^3\right )}{280 a^2 \left (a+b x^3\right )^{4/3}}+\frac{171 x}{280 a^2 \sqrt [3]{a+b x^3}} \]
Antiderivative was successfully verified.
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Rule 382
Rule 378
Rule 191
Rubi steps
\begin{align*} \int \frac{\left (a-b x^3\right )^2}{\left (a+b x^3\right )^{13/3}} \, dx &=\frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 \int \frac{\left (a-b x^3\right )^2}{\left (a+b x^3\right )^{10/3}} \, dx}{20 a}\\ &=\frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 x \left (a-b x^3\right )^2}{140 a^2 \left (a+b x^3\right )^{7/3}}+\frac{57 \int \frac{a-b x^3}{\left (a+b x^3\right )^{7/3}} \, dx}{70 a}\\ &=\frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 x \left (a-b x^3\right )^2}{140 a^2 \left (a+b x^3\right )^{7/3}}+\frac{57 x \left (a-b x^3\right )}{280 a^2 \left (a+b x^3\right )^{4/3}}+\frac{171 \int \frac{1}{\left (a+b x^3\right )^{4/3}} \, dx}{280 a}\\ &=\frac{x \left (a-b x^3\right )^3}{20 a^2 \left (a+b x^3\right )^{10/3}}+\frac{19 x \left (a-b x^3\right )^2}{140 a^2 \left (a+b x^3\right )^{7/3}}+\frac{57 x \left (a-b x^3\right )}{280 a^2 \left (a+b x^3\right )^{4/3}}+\frac{171 x}{280 a^2 \sqrt [3]{a+b x^3}}\\ \end{align*}
Mathematica [A] time = 0.0324967, size = 51, normalized size = 0.49 \[ \frac{x \left (245 a^2 b x^3+140 a^3+230 a b^2 x^6+69 b^3 x^9\right )}{140 a^2 \left (a+b x^3\right )^{10/3}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 48, normalized size = 0.5 \begin{align*}{\frac{x \left ( 69\,{b}^{3}{x}^{9}+230\,{b}^{2}{x}^{6}a+245\,b{x}^{3}{a}^{2}+140\,{a}^{3} \right ) }{140\,{a}^{2}} \left ( b{x}^{3}+a \right ) ^{-{\frac{10}{3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.977094, size = 209, normalized size = 1.99 \begin{align*} -\frac{{\left (7 \, b - \frac{10 \,{\left (b x^{3} + a\right )}}{x^{3}}\right )} b^{2} x^{10}}{70 \,{\left (b x^{3} + a\right )}^{\frac{10}{3}} a^{2}} - \frac{{\left (14 \, b^{2} - \frac{40 \,{\left (b x^{3} + a\right )} b}{x^{3}} + \frac{35 \,{\left (b x^{3} + a\right )}^{2}}{x^{6}}\right )} b x^{10}}{70 \,{\left (b x^{3} + a\right )}^{\frac{10}{3}} a^{2}} - \frac{{\left (14 \, b^{3} - \frac{60 \,{\left (b x^{3} + a\right )} b^{2}}{x^{3}} + \frac{105 \,{\left (b x^{3} + a\right )}^{2} b}{x^{6}} - \frac{140 \,{\left (b x^{3} + a\right )}^{3}}{x^{9}}\right )} x^{10}}{140 \,{\left (b x^{3} + a\right )}^{\frac{10}{3}} a^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.94679, size = 203, normalized size = 1.93 \begin{align*} \frac{{\left (69 \, b^{3} x^{10} + 230 \, a b^{2} x^{7} + 245 \, a^{2} b x^{4} + 140 \, a^{3} x\right )}{\left (b x^{3} + a\right )}^{\frac{2}{3}}}{140 \,{\left (a^{2} b^{4} x^{12} + 4 \, a^{3} b^{3} x^{9} + 6 \, a^{4} b^{2} x^{6} + 4 \, a^{5} b x^{3} + a^{6}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (b x^{3} - a\right )}^{2}}{{\left (b x^{3} + a\right )}^{\frac{13}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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